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Byju's Answer
Standard VII
Mathematics
Major Arc, Minor Arc and Semicircular Arc
Find the area...
Question
Find the area and perimeter of the sector with
(i) radius 10 cm and arc length 33 cm.
(ii) radius 55 cm and arc length 80 cm.
(iii) radius 12 cm and arc length 15.25 cm.
(iv) radius 20 cm and arc length 25 cm.
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Solution
i)
θ
360
°
×
2
π
r
=
33
㎝
⇒
θ
=
33
×
360
×
7
44
×
10
=
184
°
Area
=
189
°
360
°
×
22
7
×
10
×
10
=
165
㎠
Perimeter=Arc length
+
2
r
=
33
+
20
=
53
㎝
ii)
θ
360
°
×
2
π
r
=
80
㎝
⇒
θ
=
80
×
360
°
×
7
44
×
14
=
83.30
°
Area
=
83.30
°
360
°
×
22
7
×
55
×
55
=
2199.85
㎠
Perimeter
=
80
+
(
2
×
55
)
=
190
㎝
iii)
θ
360
°
×
2
π
r
=
15.25
㎝
⇒
θ
=
15.25
×
360
×
7
44
×
12
=
72.78
°
Area
=
72.78
°
360
°
×
22
7
×
12
×
12
=
91.50
㎠
Perimeter
=
15.25
+
(
2
×
12
)
=
39.25
㎝
iv)
θ
360
°
×
2
π
r
=
25
㎝
⇒
θ
=
25
×
360
°
×
7
44
×
20
=
71.60
°
Area
=
71.60
°
360
°
×
22
7
×
20
×
20
=
250.03
㎠
Perimeter
=
25
+
(
2
×
20
)
=
665
㎝
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