Question

Find the area bounded between the curves $y=x^2,y=\sqrt{x}$.

Answer 1

Here area is calculated on positive x-axis as $x>0$

Area=${\int }_0^1(\sqrt{x}-x^2)dx$

=${(\frac{x^{3/2}}{3/2}-\frac{x^3}{3})}_0^1$

$\Rightarrow$Area=$1$ sq.units