Question

Find the area bounded by the curve $y=\sin x$ between $x=0$ and $x=2\pi$.

• A. $2$ units
• B. $4$ units
• C. $6$ units
• D. $8$ units

Answer 1

The correct option is B $4$ units

Required Area = Area of OABO + Area BCDB

$={\int }_0^{\pi }\sin xdx+|{\int }_{\pi }^{2\pi }\sin xdx|$

$=[-\cos x{]}_0^{\pi }+|[-\cos x]{|}_{\pi }^{2\pi }|$

$=1+1+|(-1-1)|=2+|-2|=2+2=4$ units