Question

Find the area bounded by $y=x-1$, the x-axis and the ordinates x = 1, x=3.

Answer 1

$A={\int }_1^3(x-1)dx$

$={[\frac{x^2}{2}-x]}_1^3$

$=[\frac{3^2}{2}-3]-[\frac{1^2}{2}-1]$

$=\frac{3}{2}+\frac{1}{2}$

$=2$ sq.units