Find the area covered by a road roller of width $80 c m$ and diameter $140 c m$ in $40$ revolutions.

130.8 m^{2}

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143.6 m^{2}

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141.8 m^{2}

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140.8 m^{2}

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Solution

The correct option is D $140.8 m^{2}$
Curved surface area of cylinder $= 2 π r h = 2 π (70) (80) = 35200 c m^{2} = 3.52 m^{2}$
Area of 40 revolutions $= 3.52 \times 40 = 140.8 m^{2}$

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Find the area covered by a road roller of width 80cm and diameter 140cm in 40 revolutions.

The correct option is D 140.8m2Curved surface area of cylinder=2πrh=2π(70)(80)=35200cm2=3.52m2Area of 40 revolutions=3.52×40=140.8m2

Find the area covered by a road roller of width $80 c m$ and diameter $140 c m$ in $40$ revolutions.

The correct option is D $140.8 m^{2}$
Curved surface area of cylinder $= 2 π r h = 2 π (70) (80) = 35200 c m^{2} = 3.52 m^{2}$
Area of 40 revolutions $= 3.52 \times 40 = 140.8 m^{2}$