Question

Find the area enclosed between the curves $y=x$ and $y=x^2$ from $x=0$ and $x=1$

Answer 1

Area $={\int }_0^1|x-x^2|dx$

$={\int }_0^1(x-x^2)dx$

$=(\frac{1}{2}{x}^2-\frac{1}{3}{x}^3){|}_0^1$

$=\frac{1}{6}$