Find the area enclosed by the curve y = sin x and the X-axis between x = 0 and x = π.

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Solution

The given equation of the curve is y = sin x.

The required area can found by integrating y w.r.t x within the proper limits.
$∴ Area = \int_{x_{1}}^{x_{2}} y d x = \int_{0}^{π} \sin x d x = {[- \cos x]}_{0}^{π} = - \cos π - (- \cos 0) = 1 + 1 = 2 sq . unit$

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y = s i n x

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