Find the area enclosed in the first quadrant represented by the function [x] + y = 1 where [x] is the greatest integer less than or equal to x.
For x = 0 to x = 1 ⇒ y = 1
When x = 0.9999999, [x] = 0, thus y = 1
Thus the area will be very close to, but slightly less than 1
Thus, the area enclosed in the first quadrant can be represented as follows
Required area = 1×1= 1