Question

Find the area formed by the straight line $2x+3y=6$ with the co-ordinate axes.

Answer 1

Given the equation of st.line is $2x+3y=6$

or, $\frac{x}{3}+\frac{y}{2}=1$

This line cuts the co-ordinate axes at $(3,0)$ and $(0,2)$

Now, arc of triangle so formed

$=\frac{1}{2}\times 3\times 2(unit{)}^2$

$=3(units{)}^2$.