Question

Find the area in square centimeters of a triangle whose base $=18$ cm, altitude $=3.5$ cm

Answer 1

We know that the area of a triangle $=\frac{1}{2}\times$base$\times$height

Area of the triangle $=\frac{1}{2}\times 18\times 3.5=9\times 3.5=31.5$sq.cm