Question

Find the area (in square m) of the 2 m wide pathways (green) if length is twice of breadth which is equal to 8 m, of rectangle ABCD.

• A. 24
• B. 20
• C. 16
• D. 12

Answer 1

The correct option is B 20

Given Width = EF=IJ=GH=LK=MN=ON=OP=MP= 2m

length = 2$\times$breadth
AB=CD=KH=LG = 2$\times$(AD or BC)
Area of pathway = area of green rectangle
= GHKL + EIJF - MNOP ( MNOP is subtracted since its added twice)
area of pathway
= (LG$\times$GH) + (BC$\times$EF)
- area of square MNOP
= (8$\times$2) + (4$\times$2) - width ${}^2$
= (8$\times$2) + (4$\times$2) - $2^2$
= 16 +8 - 4
= 20