Find the area of a parallelogram $P Q R S,$ if $P R = 24 cm$ and $Q U = S T = 6 cm$ .

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Solution

Area of parallelogram $=$ Area (PRS) $+$ Area (PQR)
$= \frac{1}{2} (P R) (S T) + \frac{1}{2} (P R) (U Q)$
$= \frac{1}{2} (P R) (S T + U Q)$
$= \frac{1}{2} \times 24 \times 12 = 144 {cm}^{2}$

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Find the area of a parallelogram PQRS, if PR=24 cm and QU=ST=6 cm.

Area of parallelogram = Area (PRS) + Area (PQR)=12(PR)(ST)+12(PR)(UQ)=12(PR)(ST+UQ)=12×24×12=144 cm2

Find the area of a parallelogram $P Q R S,$ if $P R = 24 cm$ and $Q U = S T = 6 cm$ .

Area of parallelogram $=$ Area (PRS) $+$ Area (PQR)
$= \frac{1}{2} (P R) (S T) + \frac{1}{2} (P R) (U Q)$
$= \frac{1}{2} (P R) (S T + U Q)$
$= \frac{1}{2} \times 24 \times 12 = 144 {cm}^{2}$