Find the area of a parallelogram whose perimeter is $32 c m$ and sides are in the ratio $3$ and $5$ and the perpendicular to the longest side is $8 c m$

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Solution

Height is $- 8 c m$
given perimeter $- 32 c m$
sides ratio $- 3 : 5$
then sides are 6 and10 cm respectively $a r e a = b a s e \times h e i g h t$
$8 \times 6 = 48 c m^{2}$

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Find the area of a parallelogram whose perimeter is 32cm and sides are in the ratio 3 and 5 and the perpendicular to the longest side is 8cm

Height is−8cmgiven perimeter−32cmsides ratio−3:5 then sides are 6 and10 cm respectively area=base×height8×6=48cm2

Find the area of a parallelogram whose perimeter is $32 c m$ and sides are in the ratio $3$ and $5$ and the perpendicular to the longest side is $8 c m$

Height is $- 8 c m$
given perimeter $- 32 c m$
sides ratio $- 3 : 5$
then sides are 6 and10 cm respectively $a r e a = b a s e \times h e i g h t$
$8 \times 6 = 48 c m^{2}$