Question

Find the area of a quadrant of a circle whose circumference is 22 cm

Answer 1

$\begin{array}{c}wehave\\ C=22cm\\ \Rightarrow 2\pi r=22cm\\ \Rightarrow 2\times \frac{22}{7}\times r=22\\ \therefore r=3.5cm\\ Now,\\ areaofquadrantofacircle=\frac{\pi r^2}{4}\\ =\frac{22}{7}\times \frac{{\left(3.5\right)}^2}{4}\\ =\frac{22\times 12.25}{28}\\ =9.625c{m}^2.\end{array}$