Question

Find the area of a quadrant of a circle whose circumference is $44$ cm.

Answer 1

Circumference of circle $=2\pi r$

Given, $2\pi r=44$

$\Rightarrow r=\frac{44}{2\pi }=\frac{22}{\pi }$

Area of quadrant $=\frac{\pi r^2}{4}$

$\Rightarrow A=\frac{\pi {\left(\frac{22}{\pi }\right)}^2}{4}\Rightarrow A=\frac{\pi \times 22\times 22}{\pi \times \pi \times 4}\Rightarrow A=\frac{121}{\pi }$