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Question

Find the area of a quadrilateral ABCD in which AB = 3 cm , BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

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Solution

In ABC
2s = 5+4+3 ⇒ s = 6 cm
Area of ΔABC
=s(sa)(sb)(sc)=6(65)(64)(63)=6(1)(2)(3)=36=6 cm2 For area of ADC, 2s=5+4+5 s=7 cm Area of ADC=s(sa)(sb)(sc)=7(75)(75)(74)=7×2×2×384=9.16 cm2 Area of quad ABCD=Area of(ABC+ADC)
=6+9.16
=15.16 cm215.2 cm2


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