Find the area of a quadrilateral piece of land one of whose diagonals is $32$ m log and are the perpendicular from the vertices are $20$ m and $12$ m?

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Solution

Given:-
Length of diagonal $= 32 m$
Length of perpendicular drawn from the remaining two vertices are $20 m$ and $12 m$ .
As we know that,
Area of quadrilateral $= \frac{1}{2} \times$ length of diagonal $\times$ sum of length of perpendicular drawn from the remaining two vertices
Therefore,
Area of given quadrilateral $= \frac{1}{2} \times 32 \times (20 + 12) = 16 \times 32 = 512 m^{2}$
Thus the area of given quadrilateral is $512 m^{2}$ .
Hence the correct answer is $512 m^{2}$ .

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Find the area of a quadrilateral piece of land one of whose diagonals is 32 m log and are the perpendicular from the vertices are 20 m and 12 m?

Find the area of a quadrilateral piece of land one of whose diagonals is $32$ m log and are the perpendicular from the vertices are $20$ m and $12$ m?