Find the area of a rectangle, if the length of the rectangle is x and the breadth is twice the length the area of the rectangle?

A = $x^{2}$

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A = $4 x$

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A = $2 x^{2}$

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Solution

The correct option is C
A = $2 x^{2}$

It is given that the length of the rectangle is x and the breadth is twice the length

i.e. Breadth = $2 \times (x)$

Therefore the area of the rectangle = $(x) \times (2 x)$

= $2 x^{2}$

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Find the area of a rectangle, if the length of the rectangle is x and the breadth is twice the length the area of the rectangle?

The correct option is C A = 2x2 It is given that the length of the rectangle is x and the breadth is twice the length i.e. Breadth = 2×(x) Therefore the area of the rectangle =(x)×(2x) = 2x2

The correct option is C
A = $2 x^{2}$

It is given that the length of the rectangle is x and the breadth is twice the length

i.e. Breadth = $2 \times (x)$

Therefore the area of the rectangle = $(x) \times (2 x)$

= $2 x^{2}$