Find the area of a rectangular park which is 363-5m long and 162-3 m broad-

Length of rectangular park = 363/5 m=183/5 m and breadth = 162/3=50/3 m ∴ Area = Length × Breadth =183/5×50/3=183×50/5×3 km^2 =9150/15 km^2=610 km^2 Ans. ...

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Standard VI

Mathematics

Area of Rectangle

Find the area...

Question

Find the area of a rectangular park which is $36 \frac{3}{5} m long and 16 \frac{2}{3} m$ broad.

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Solution

Length of rectangular park = $36 \frac{3}{5} m = \frac{183}{5} m$

and breadth = $16 \frac{2}{3} = \frac{50}{3} m$

$∴$ Area = Length $\times$ Breadth

$= \frac{183}{5} \times \frac{50}{3} = \frac{183 \times 50}{5 \times 3} k m^{2} = \frac{9150}{15} k m^{2} = 610 k m^{2} A n s .$

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Find the area of a rectangular park which is 3635mlong and 1623m broad.

Length of rectangular park = 3635 m=1835 m and breadth = 1623=503 m ∴ Area = Length × Breadth =1835×503=183×505×3 km2=915015 km2=610 km2 Ans.

Find the area of a rectangular park which is $36 \frac{3}{5} m long and 16 \frac{2}{3} m$ broad.

Length of rectangular park = $36 \frac{3}{5} m = \frac{183}{5} m$

and breadth = $16 \frac{2}{3} = \frac{50}{3} m$

$∴$ Area = Length $\times$ Breadth

$= \frac{183}{5} \times \frac{50}{3} = \frac{183 \times 50}{5 \times 3} k m^{2} = \frac{9150}{15} k m^{2} = 610 k m^{2} A n s .$