Find the area of a regular hexagon with side of $15$ m and apothem is $20$ m.

910

m^{2}

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920

m^{2}

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900

m^{2}

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901

m^{2}

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Solution

The correct option is C $900$ $m^{2}$
Area of regular hexagon = $\frac{p e r i m e t e r \times a p o t h e m}{2}$
Perimeter = number of sides $\times$ side length
Perimeter = $6 \times 15 = 90$ m
So, Area = $\frac{90 \times 20}{2}$
Area = $900$ $m^{2}$

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Find the area of a regular hexagon with side of 15 m and apothem is 20 m.

The correct option is C 900 m2Area of regular hexagon = perimeter×apothem2Perimeter = number of sides × side lengthPerimeter = 6×15=90 mSo, Area = 90×202Area = 900 m2

Find the area of a regular hexagon with side of $15$ m and apothem is $20$ m.

The correct option is C $900$ $m^{2}$
Area of regular hexagon = $\frac{p e r i m e t e r \times a p o t h e m}{2}$
Perimeter = number of sides $\times$ side length
Perimeter = $6 \times 15 = 90$ m
So, Area = $\frac{90 \times 20}{2}$
Area = $900$ $m^{2}$