Find the area of a rhombus whose side is $6 c m$ and altitude is $4 c m$ . If one of the diagonals is $8 c m$ long, find the length of the other diagonal.

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Solution

Area $= b$ $\times$ $h = 6$ $\times$ $4 = 24$ cm $^{2}$ .
Also area = $\frac{1}{2} (d_{1} \times d_{2})$
or, $\frac{1}{2} (8$ $\times d_{2}$ $) = 24$
or, $d_{2}$ $= 6$ cm.

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Find the area of a rhombus whose side is 6cm and altitude is 4cm. If one of the diagonals is 8cm long, find the length of the other diagonal.

Area =b×h=6×4=24 cm2.Also area =12(d1×d2)or, 12(8×d2)=24or, d2=6 cm.

Find the area of a rhombus whose side is $6 c m$ and altitude is $4 c m$ . If one of the diagonals is $8 c m$ long, find the length of the other diagonal.

Area $= b$ $\times$ $h = 6$ $\times$ $4 = 24$ cm $^{2}$ .
Also area = $\frac{1}{2} (d_{1} \times d_{2})$
or, $\frac{1}{2} (8$ $\times d_{2}$ $) = 24$
or, $d_{2}$ $= 6$ cm.