Find the area of a right-angled triangle whose base is 3 cm and height is 4 cm.

$6 c m^{2}$

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$9 c m^{2}$

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$8 c m^{2}$

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$5 c m^{2}$

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Solution

The correct option is A
$6 c m^{2}$

Area of right triangle $= \frac{1}{2} \times b a s e \times h e i g h t$
$= \frac{1}{2} \times 3 c m \times 4 c m$
$= 6 c m^{2}$

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Similar questions

In a right angled triangle if the base is 3 cm and perpendicular is 4 cm.What is the area of that triangle?

The sides of a right-angled triangle are p, p+1 and 5. Find the area of triangle, if the longest side measures 5 cm.

22

m^{2}

2 m

The angles of a triangle are $(2 x)^{0}, (4 x)^{0}, (6 x)^{0}$ .

What is the area of a right angled triangle whose base is (x + 3) cm and height is $(\frac{x}{5})$ cm?

△ P Q R

A = \frac{1}{2} \times 7 \times 5 c m^{2}

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