Question

Find the area of a right angled triangle whose sides containing the right angle are of lengths 20.8 m and 14.7 m.

Answer 1

In a right-angled triangle, the sides containing the right angles are of lengths 20.8 m and 14.7 m.
Let the base be 20.8 m and the height be 14.7 m.
Then,
Area of a triangle = $\frac{1}{2}\times \mathrm{Base}\times \mathrm{Height}$

= $\frac{1}{2}\times 20.8\times 14.7=152.88{\mathrm{m}}^2$