Find the area of a right triangle having base = 24 cm and hypotenuse = 25 cm.

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Solution

Consider ΔABC.
Here, ∠B = 90°
AB = 24 cm
AC = 25 cm

Now, AB² + BC² = AC²
⇒ BC² = AC² - AB²
=(25² - 24²)
=(625 - 576)
= 49
⇒ BC = $(\sqrt{49})$ cm = 7 cm
Area of ΔABC= $(\frac{1}{2} \times BC \times AB)$ sq. units
= $(\frac{1}{2} \times 7 \times 24)$ cm² = 84 cm²
Hence, area of the right angled triangle is 84 cm².

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