Question

Find the area of a traingle ABC.

• A. $\frac{ch}{2}{\text{unit}}^2$
• B. $\frac{bh}{2}{\text{unit}}^2$
• C. $\frac{ah}{2}{\text{unit}}^2$
• D. $\frac{abch}{2}{\text{unit}}^2$

Answer 1

The correct option is A $\frac{ch}{2}{\text{unit}}^2$

The perpendicular line from the vertex 'B' to the line AC is called the height of a triangle ABC and it is equal to $h$.

Since, BC is perpendicular to AC, so AC is the base of a triangle ABC.
Base of the triangle ABC $=AC=c$

Hence,
Height of the triangle $=h$ unit
Base of the triangle $=c$ unit
As we know,
$\text{Area of}△ABC=\frac{1}{2}\times \text{Base}\times \text{Height}$

$=\frac{1}{2}\times c\times h$

$=\frac{ch}{2}{\text{unit}}^2$