Find the area of a trapezium whose parallel sides are $24 c m$ and $20 c m$ and the distance between them is $15 c m$ .

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Solution

Area of a trapezium $= \frac{1}{2} \times$ Sum of parallel sides $\times$ Distance between them
$= \frac{1}{2} \times (24 + 20) \times 15$
$= \frac{1}{2} \times 44 \times 15$
$= 22 \times 15$
$= 330 c m^{2}$

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A parallelogram has 1 set parallel sides = 20 cm and another set = 24 cm. If the distance between the 24 cm sides is 15 cm, then the distance between the 20 cm sides is ____ cm

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Find the area of a trapezium whose parallel sides are 24cm and 20cm and the distance between them is 15cm.

Area of a trapezium =12× Sum of parallel sides × Distance between them=12×(24+20)×15=12×44×15=22×15=330cm2

Find the area of a trapezium whose parallel sides are $24 c m$ and $20 c m$ and the distance between them is $15 c m$ .

Area of a trapezium $= \frac{1}{2} \times$ Sum of parallel sides $\times$ Distance between them
$= \frac{1}{2} \times (24 + 20) \times 15$
$= \frac{1}{2} \times 44 \times 15$
$= 22 \times 15$
$= 330 c m^{2}$