Question

Find the area of a trapezium whose parallel sides are 38.7 cm and 22.3 cm, and the distance between them is 16 cm.

Answer 1

$\mathrm{Area}\mathrm{of}\mathrm{a}\mathrm{trapezium}=\frac{1}{2}\times \left(\mathrm{Sum}\mathrm{of}\mathrm{parallel}\mathrm{sides}\right)\times \left(\mathrm{Distance}\mathrm{between}\mathrm{them}\right)$

$$\begin{gathered} =\left\{\frac{1}{2}\times \left(38.7+22.3\right)\times 16\right\}{\mathrm{cm}}^2 \\ =\left(\frac{1}{2}\times 61\times 16\right){\mathrm{cm}}^2 \\ =\left(61\times 8\right){\mathrm{cm}}^2 \\ =488{\mathrm{cm}}^2 \end{gathered}$$

$\mathrm{Hence},\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{trapezium}\mathrm{is}488{\mathrm{cm}}^2.$