Question

# Find the area of a triangle if its sides are  $$9 cm , 12cm\ and\ 15cm$$

Solution

## We know in triangle if the three sides are $$a,b,c$$ then the area of the triangle isArea=$$\sqrt{s×(s-a) ×(s-b) ×(s-c)}$$Where $$s=\dfrac{(a+b+c)}{2}$$Given $$a=9,b=12,c=15$$Therefore $$s=\dfrac{(9+12+15)}{2}=18$$Therefore area $$=\sqrt{18×9×6×3}=54$$So  the area of the triangle is $$54cm^2$$Mathematics

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