Find the area of a triangle, two sides of which are $8 c m$ and $11 c m$ and the perimeter is $32 c m$

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Solution

Perimeter of $△ = 32 c m$
$\Rightarrow$ Third side $= 32 - (8 + 11) = 32$ cm
ar. of $△ = \sqrt{s (s - a) (s - b) (s - c)}$
$S = \frac{32}{2} = 16$
ar $= \sqrt{16 (16 - 8) (16 - 11) (16 - 13)}$
$= \sqrt{16 \times 8 \times 5 \times 3}$
$= 43.82 {c m}^{2}$

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