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Question

Find the area of a triangle two sides of which are 8 cm and 11 cm and perimeter is 32 cm.
1064978_30be6f66f3cd44699342debe6110d3fc.jpg

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Solution

We are given,
Sides of ABC
are a,b & c(in cm)
Let a=8
b=11
here we have perimeter,
i.e., 32 cm.
So, a+b+c=32 cm
c=32(a+b)
=32(8+12)
c=3219
c=13 cm
Now, the semi perimeter will be
S=perimeter2=322=16 cm
Now, Area =S.(sa)(sb)(sc)
=16(168)(1611)(1613)
=16×8×5×3
=2×2×2×2×2×2×2×3×5
=2×2×2×2×3×5
Area =830 cm×cm
Area =830 cm2

1424435_1064978_ans_c6d97ec201e24edd969e59a1b8dc7c1d.png

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