Question

Find the area of a triangle whose base and altitude are 5 cm and 4 cm respectively.

Answer 1

In $\Delta ABC$,
Base BC= 5 cm
Altitude AD =4cm

$\therefore Area=\frac{base\times altitude}{2}$
= $\frac{BC\times AD}{2}=\frac{5\times 4}{2}=10c{m}^2$