Find the area of a triangle whose base and corresponding height are 12 cm and 4.8 cm, respectively.

57.6 cm²

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28.8 cm²

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14.4 cm²

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7.2 cm²

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Solution

The correct option is B 28.8 cm²
$A r e a o f a t r i a n g l e = \frac{1}{2} \times b a s e \times c o r r e s p o n d i n g h e i g h t = \frac{1}{2} \times 12 c m \times 4.8 c m = 28.8 c m ²$

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