Question

Find the area of a triangle whose base is $12$cm and height is $5\sqrt{2}cm.$

Answer 1

Base of triangle =$12cm$

Height of triangle =$5\sqrt{2}cm$

Area =$\frac{1}{2}(base\times height)$

$=\frac{1}{2}\times 12\times 5\sqrt{2}$

$=30\sqrt{2}c{m}^2$
$=42.42c{m}^2$