Question

Find the area of a triangle whose base is $18cm$ and altitude is $10cm$.

Answer 1

We know that,

$$\begin{gathered} Areaoftriangle=\frac{1}{2}\times base\times height \\ Areaoftriangle=\frac{1}{2}\times 18\times 10=90c{m}^2 \end{gathered}$$

Hence, the area of triangle is $90c{m}^2$