Question

Find the area of a triangle whose sides are $18cm,24cm,30cm$.
Also, find the length of altitude corresponding to the largest side of the triangle.

Answer 1

$a=18cm,b=24cm,c=30cm$

$1)s=\frac{a+b+c}{2}=\frac{72}{2}=36$

$area=\sqrt{s(s-a)(s-b)(s-c)}$

$=\sqrt{36\times 18\times 12\times 6}$

$=\sqrt{36\times 36\times 6\times 6}$

$36\times 6=16c{m}^2$

$2)shortestside=18cm$

$letattitude=h$

$area=216c{m}^2$

$\frac{1}{2}\times b\times h=216$

$h=\frac{2\times 216}{18}=24cm$