Question

Find the area of a triangle whose sides are $8$ cm, $15$ and $17$ cm.

Answer 1

Here, P = 8+15 +17= 21 cm

$S=\frac{a+b+c}{2}$

So $S=\frac{40}{2}=20cm$

$s-a=12,s-b=5,s-c=3$

Area of triangle=$\sqrt{S(S-a)(S-b)(S-c)}$

$=\sqrt{20\left(12\right)\left(5\right)\left(3\right)}$

$=\sqrt{40\left(12\right)\left(5\right)\left(3\right)}$

$=60$