Question

Find the area of a triangle whose sides area 3 cm, 4 cm and 5cm respectively.

Answer 1

Sides of triangle are 3 cm, 4 cm and 5 cm

$\therefore s=\frac{a+b+c}{2}=\frac{3+4+5}{2}=\frac{12}{2}=6cm\therefore Area=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{6\times (6-3)(6-4)(6-5)}=\sqrt{6\times 3\times 2\times 1}=\sqrt{36}=6c{m}^2$