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Question

Find the area of a triangle whose vertices are

(i) (6, 3) (−3, 5) and (4, −2)

(ii) (at12, 2at1), (at22,2at2) and (at32,2at3)

(iii) (a, c + a), (a, c) and (−a, c − a)

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Solution

We know area of triangle formed by three points is given by

(i) The vertices are given as (6, 3), (−3, 5), (4, −2).

(ii) The vertices are given as .


(iii)

The vertices are given as .


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