Question

Find the area of a triangle with sides 6m, 8m amd 10m.

Answer 1

The area of a triangle with sides of length $6cm,8cm$ and $10cm$ has to be determined.

This is a right triangle with perpendicular sides of length $6$ and $8cm.$

The area can be derived using Heron's theorem.

The area is given by $\sqrt{s.(s-a).(s-b).(s-c)}$

where $s$ is semi perimeter equal to $\frac{6+8+10}{2}=12$

$a=6,b=8$ and $c=10.$

The area of the triangle is equal to $\sqrt{\mathrm{12.6.4.2}}=\sqrt{576}=24c{m}^2$

Hence, the answer is $24c{m}^2$