Question

Find the area of an acute triangle of a given image.

• A. $36{\text{m}}^2$
• B. $36\text{m}$
• C. $18{\text{m}}^2$
• D. $48{\text{m}}^2$

Answer 1

The correct option is A $36{\text{m}}^2$

Let name the vertice of a triangle as ABC
Given,
Base of a triangle$=BC=12$ m
Height of a triangle$=AD=6$ m
Let's consider a triangle $\Delta ABC$ as shown.
Here $BC=12$ m and $AD=6$ m
As we know,
Area of$△ABC=\frac{1}{2}\times \text{Base}\times \text{Height}$
$\Rightarrow \frac{1}{2}\times 12\times 6=36{\text{m}}^2$

Option (a) is correct.