Question

Find the area of an equilateral triangle having each side 4 cm.

Answer 1

Each side of equilateral triangle (a) = 4cm
$\therefore$ Area = $\frac{\sqrt{3}}{4}(side{)}^2$
= $\frac{\sqrt{3}}{4}\times (4{)}^{2}c{m}^2=\frac{\sqrt{3}\times 4\times 4}{4}c{m}^2=4\sqrt{3}c{m}^2$