Find the area of an equilateral triangle of side 10 cm-A- 18 -3 cm 2B- 25 -3 cm 2C- 12 -3 cm 2D- 27 -3 cm 2

The correct option is B 25√(3) cm^2 Area of equilateral triangle = √(3)/4 side^2 = √(3)/4 10^2 =25√(3) cm^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Identifying Shapes and Areas of Different Regular Figures

Find the area...

Question

Find the area of an equilateral triangle of side 10 cm.

$18 \sqrt{3} c m^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$25 \sqrt{3} c m^{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$12 \sqrt{3} c m^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$27 \sqrt{3} c m^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$25 \sqrt{3} c m^{2}$

Area of equilateral triangle = $\frac{\sqrt{3}}{4}$ $s i d e^{2}$

$= \frac{\sqrt{3}}{4} 10^{2}$

$= 25 \sqrt{3} c m^{2}$

Suggest Corrections

Similar questions

In $Δ A B C, ∠ A = ∠ B = 30^{\circ}, A B = 12 c m$ , the area of the triangle will be equal to

Q. Find the area of an equilateral triangle of side 6 cm.

$Each side of an equilateral triangle measures 8 cm. The area of the triangle is (a) 8 \sqrt{3} c m^{2} (b) 16 \sqrt{3} c m^{2} (c) 32 \sqrt{3} c m^{2} (d) 48 c m^{2}$

Area of a regular hexagon having side length as 2 cm is -

A square and an equilateral triangle have equal perimeters. If the diagonal of the square is $12 \sqrt{2} c m$ , then the area of the triangle is:

Join BYJU'S Learning Program

Find the area of an equilateral triangle of side 10 cm.

The correct option is B 25√3 cm2 Area of equilateral triangle = √34 side2 =√34102 =25√3 cm2

The correct option is B
$25 \sqrt{3} c m^{2}$

Area of equilateral triangle = $\frac{\sqrt{3}}{4}$ $s i d e^{2}$

$= \frac{\sqrt{3}}{4} 10^{2}$

$= 25 \sqrt{3} c m^{2}$