Question

Find the area of an equilateral triangle of side 6 cm.

Answer 1

$$\begin{gathered} \mathrm{Area}\mathrm{of}\mathrm{an}\mathrm{equilateral}\mathrm{traingle}=\left(\frac{\sqrt{3}}{4}\times {\left(\mathrm{side}\right)}^2\right)\mathrm{square}\mathrm{units} \\ =\left(\frac{\sqrt{3}}{4}\times 6\times 6\right){\mathrm{cm}}^2 \end{gathered}$$
$$\begin{gathered} =\left(\frac{\sqrt{3}}{4}\times 36\right){\mathrm{cm}}^2 \\ =9\sqrt{3}{\mathrm{cm}}^2 \end{gathered}$$
$\mathrm{Hence},\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{an}\mathrm{equilateral}\mathrm{triangle}\mathrm{is}9\sqrt{3}{\mathrm{cm}}^2$.