Question

Find the area of an equilateral triangle with side $2\sqrt{3}cm$.

Answer 1

Given length of the side is $a=2\sqrt{3}cm$

As we know area of an equilateral triangle with side $a$

$=\frac{\sqrt{3}}{4}{a}^2$

Substitute value of $a$, we get

$=\frac{\sqrt{3}}{4}\times (2\sqrt{3}{)}^2$
$=\frac{\sqrt{3}}{4}\left(12\right)$
$=3\sqrt{3}c{m}^2$.
Hence, the area of given triangle is $3\sqrt{3}c{m}^2$.