Question

Find the area of an isosceles right-angled triangle whose hypotenuses is $8$ cm.

• A. $32c{m}^2$
• B. $24c{m}^2$
• C. $16c{m}^2$
• D. none of these

Answer 1

The correct option is C $16c{m}^2$

$x^2+x^2=64$

${2x}^2=64$

$x^2=32$

$x=\sqrt{32}=4\sqrt{2}cm$

$\therefore$ area $=\frac{1}{2}\times 4\sqrt{2}\times 4\sqrt{2}{cm}^2$

$=8\times 2{cm}^2=16{cm}^2$