Question

Find the area of an isosceles triangle with two equal sides as 5 cm each and the third side as 8 cm.

Answer 1

Dear student,
$$\begin{gathered} Sidesoftriangleare5cm,5cm,and8cm \\ Leta,bandcarethesidesofisoscelectriangle. \\ thensemiperimeter,s=\frac{a+b+c}{2}=\frac{5+5+8}{2}=\frac{18}{2}=9 \\ Area=\sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)} \\ =\sqrt{9(9-5)(9-5)(9-8)} \\ =\sqrt{9\times 4\times 4\times 1} \\ =\sqrt{3\times 3\times 2\times 2\times 2\times 2} \\ =3\times 2\times 2 \\ =12c{m}^2 \\ Thus,theareaofissoscelestriangleis12c{m}^2. \end{gathered}$$
Regards