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Byju's Answer
Standard X
Mathematics
Area of a Triangle Given Its Vertices
Find the area...
Question
Find the area of
Δ
PQR whose vertices are
P
(
2
,
1
)
,
Q
(
3
,
4
)
and
R
(
5
,
2
)
.
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Solution
P
(
2
,
1
)
Q
(
3
,
4
)
R
(
5
,
2
)
Area of triangle
=
1
2
|
x
1
(
y
2
−
y
3
)
+
x
2
(
y
3
−
y
1
)
+
x
3
(
y
1
−
y
2
)
|
=
1
2
|
2
(
4
−
2
)
+
3
(
2
−
1
)
+
5
(
1
−
4
)
|
=
1
2
|
2
(
2
)
+
3
(
1
)
+
5
(
−
3
)
|
=
1
2
|
|
4
+
3
−
15
|
=
8
2
=
4
s
q
.
u
n
i
t
s
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Similar questions
Q.
Find the area of
△
P
Q
R
whose vertices are
P
(
2
,
1
)
,
Q
(
3
,
4
)
and
R
(
5
,
2
)
.
Q.
P
(
2
,
1
)
,
Q
(
2
,
5
)
and
R
(
k
,
5
)
are the three vertices of
△
P
Q
R
in which
∠
Q
=
90
o
. If the area of
△
P
Q
R
is
10
u
n
i
t
2
, the value of
k
is:
Q.
The vertices of
△
P
Q
R
are
P
(
2
,
1
)
,
Q
(
−
2
,
3
)
and
R
(
4
,
5
)
. Find equation of the median through the vertex
R
.
Q.
Using integration, find the area of the triangle
P
Q
R
, whose vertices are
P
(
2
,
5
)
,
Q
(
4
,
7
)
and
R
(
6
,
2
)
.
Q.
P, Q and R are the mid points of the sides of
Δ
ABC and X, Y and Z are the mid points of
Δ
PQR. If area of
Δ
XYZ is
10
then find the area of
Δ
PQR.
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