Question

Find the area of given trapezium

• A. $88sq.cm$
• B. $44sq.cm$
• C. $172sq.cm$
• D. $22sq.cm$

Answer 1

The correct option is A $88sq.cm$

In given figure a perpendicular drawn from point C this cut line AB at point E

Then AB|| DC and perpendicular drawn from point C this cut line AB at point E

Then AE=DC= 8 cm and EB =14-8 =6 cm

Then triangle CEB

$(CB{)}^2=(EC{)}^2+(EB{)}^2\Rightarrow (CB{)}^2=(10{)}^2+(6{)}^2=100-36=64\Rightarrow CB=8$ cm

IN this trapezium CB is the height of trapezium

Then area of given trapezium=$\frac{1}{2}(AB+DC)CB=\frac{1}{2}(14+8)8=88$ sq cm