Find the area of given triangle in $c m^{2}$ [3 Marks]

Open in App

Solution

Concept : 0.5 Mark
Application : 0.5 Mark
Calculation : 2 Marks
Semi perimeter of a triangle = $\frac{(a + b + c)}{2} = \frac{10 + 6 + 8}{2} = 12 c m$

Area of a triangle = $\sqrt{s (s - a) (s - b) (s - c)}$
= $\sqrt{12 (12 - 8) (12 - 10) (12 - 6)}$
= $\sqrt{576}$
= 24 $c m^{2}$

Suggest Corrections

Similar questions

In the given fig. $θ$ ABC is an equilateral triangle inscribed in a circle of radius 4 cm and centre O. Show that the area of the shaded region is $\frac{4}{3} (4 π - 3 \sqrt{3}) c m^{2}$ . [4 MARKS]

Q. The area of an equilateral triangle is

49 \sqrt{3} c m^{2}

. Taking each angular point as centre, a circle is described with radius equal to half the length of the side of the triangle. Find the area of the triangle not included in the circle. [ 4 MARKS ]

PQRS is a parallelogram with PS = 4 cm and AR $∥$ PB. If Area of triangle APS = 48 $c m^{2}$ , find the height of triangle QRB. [2 MARKS]

Q. In the given figure, find the area of parallelogram ABCD, if the area of the shaded triangle is

9 c m^{2}

Q. The area of an equilateral triangle is

25 \sqrt{3}

c m^{2}

. Find the side of the triangle (in cm)

Join BYJU'S Learning Program

Find the area of given triangle in cm2 [3 Marks]

Concept : 0.5 Mark Application : 0.5 Mark Calculation : 2 Marks Semi perimeter of a triangle = (a+b+c)2=10+6+82=12 cm Area of a triangle = √s(s−a)(s−b)(s−c) = √12(12−8)(12−10)(12−6) = √576 = 24 cm2

Find the area of given triangle in $c m^{2}$ [3 Marks]

Concept : 0.5 Mark
Application : 0.5 Mark
Calculation : 2 Marks
Semi perimeter of a triangle = $\frac{(a + b + c)}{2} = \frac{10 + 6 + 8}{2} = 12 c m$

Area of a triangle = $\sqrt{s (s - a) (s - b) (s - c)}$
= $\sqrt{12 (12 - 8) (12 - 10) (12 - 6)}$
= $\sqrt{576}$
= 24 $c m^{2}$