Find the area of given triangle in $c m^{2}$ [3 Marks]

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Solution

Concept : 0.5 Mark
Application : 0.5 Mark
Calculation : 2 Marks
Semi perimeter of a triangle = $\frac{(a + b + c)}{2} = \frac{10 + 6 + 8}{2} = 12 c m$

Area of a triangle = $\sqrt{s (s - a) (s - b) (s - c)}$
= $\sqrt{12 (12 - 8) (12 - 10) (12 - 6)}$
= $\sqrt{576}$
= 24 $c m^{2}$

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Find the area of given triangle in cm2 [3 Marks]

Concept : 0.5 Mark Application : 0.5 Mark Calculation : 2 Marks Semi perimeter of a triangle = (a+b+c)2=10+6+82=12 cm Area of a triangle = √s(s−a)(s−b)(s−c) = √12(12−8)(12−10)(12−6) = √576 = 24 cm2

Find the area of given triangle in $c m^{2}$ [3 Marks]

Concept : 0.5 Mark
Application : 0.5 Mark
Calculation : 2 Marks
Semi perimeter of a triangle = $\frac{(a + b + c)}{2} = \frac{10 + 6 + 8}{2} = 12 c m$

Area of a triangle = $\sqrt{s (s - a) (s - b) (s - c)}$
= $\sqrt{12 (12 - 8) (12 - 10) (12 - 6)}$
= $\sqrt{576}$
= 24 $c m^{2}$